2w^2+16w=-32

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Solution for 2w^2+16w=-32 equation: 



2w^2+16w=-32

We move all terms to the left:

2w^2+16w-(-32)=0

We add all the numbers together, and all the variables

2w^2+16w+32=0

a = 2; b = 16; c = +32;
Δ = b2-4ac
Δ = 162-4·2·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{-16}{4}=-4$

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